(3x-1)(x^2+5x-4)=0

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Solution for (3x-1)(x^2+5x-4)=0 equation: 


Simplifying
(3x + -1)(x2 + 5x + -4) = 0

Reorder the terms:
(-1 + 3x)(x2 + 5x + -4) = 0

Reorder the terms:
(-1 + 3x)(-4 + 5x + x2) = 0

Multiply (-1 + 3x) * (-4 + 5x + x2)
(-1(-4 + 5x + x2) + 3x * (-4 + 5x + x2)) = 0
((-4 * -1 + 5x * -1 + x2 * -1) + 3x * (-4 + 5x + x2)) = 0
((4 + -5x + -1x2) + 3x * (-4 + 5x + x2)) = 0
(4 + -5x + -1x2 + (-4 * 3x + 5x * 3x + x2 * 3x)) = 0
(4 + -5x + -1x2 + (-12x + 15x2 + 3x3)) = 0

Reorder the terms:
(4 + -5x + -12x + -1x2 + 15x2 + 3x3) = 0

Combine like terms: -5x + -12x = -17x
(4 + -17x + -1x2 + 15x2 + 3x3) = 0

Combine like terms: -1x2 + 15x2 = 14x2
(4 + -17x + 14x2 + 3x3) = 0

Solving
4 + -17x + 14x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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